Showing posts with label colum. Show all posts
Showing posts with label colum. Show all posts

Wednesday, March 28, 2012

Need Help 2

I am currently converting an access DB to MS SQL.
I am currently trying to figure out how to code this
I need the count of all rows in colum TERM that is > 1 when its grouped by the COLUM NAME
Anyone got any Ideas,i'm not sure wheter i get it right.

hope that it was the thing that you ask for.

Select TERM,Count(<table key>) as Cnt from <Table \name>
Wher TERM > 1
Group by TERM.

If I didn't get it right then just forget about it.
:D|||select count(*) from tbl
where term in
(
select term from tbl group by name having count(*) > 1
)

Monday, March 26, 2012

Need help

This may seem like a dumb question, but here is what I am trying to do,
Lets say, I have a TABLE that has colums
A B C D
Now, I have added a 5th colum E
I want to populate E with D
I can't seem to get the insert command right,
Anyone ??Hello, please try this:

UPDATE myTable SET E=D;

Originally posted by ChrisWBates
This may seem like a dumb question, but here is what I am trying to do,

Lets say, I have a TABLE that has colums

A B C D

Now, I have added a 5th colum E

I want to populate E with D

I can't seem to get the insert command right,

Anyone ??|||Or more fully

UPDATE A SET E=D FROM myTable99 A
GOsql

Friday, March 23, 2012

Need expression help ASAP

I have a report in ssrs where it has a colum with dates in it I has and other colum with either a $0.00 amount or and amount paid. I need a colum which which calculates only the number of days from the date colum that when the other colum =0 it gives me the total number of days. VS.net SQL 2005 SSRS C#

example of what needed:

Invoice amount | Date of Invoice| Amount received | number days past due

$100.00 06/01/2007 0.00 18 days ( this is what I need)

can some one explain.

Here are my expressions

FormatCurrency(Fields!Grossamtbilled.value)

FormatDateTime(Fields!EXPR1.Value,2)

FormatCurrency(Fields!RCVAMOUNT.Value)

I'm not sure what expression you would use when creating a report, but it would be fairly easy to do it in the original SQL Statement (by using a mixture of the CASE and DateDiff functions).

sql