Need help converting date format.

Hi and thanx for reading my post..

I have a reg_date field in my MSSQL DB which is formatted like this :

dd.mm.yy tt:mm:ss (eks. 24.12.03 18:00:03)

What i want to do is get the 8 first chars from this string so i end up with only : 24.12.03

Have tried different variations of : convert(char(8) but not sure how i do this really..

Have already searched the net for a solution but had to post it since i didn't find anything useful..

Hope someone can help me out

Best regards
Mirador-/select ((CONVERT(CHAR(6),getdate(),104)) + RIGHT(CONVERT(CHAR(10),getdate(),104),2))|||select (CONVERT(CHAR(10),getdate(),4))

using 104 adds the century to the year, which then has to be eliminated in the first response. Just using 4 returns only the last two digits of the year. Be carefule though, as this type of date format will be a problem in your code in 96 years ;-)|||Sorry, make that CHAR(8).|||Hi and thanx for the quick reply !

Have tried the code but still got trouble with this errormsg i get :

--> Incorrect syntax near '.03.'

This is the code :

SELECT bla1, bla2, bla3, bla4 FROM TABLE WHERE blabla = 1 and blabla = 0 and CONVERT(char(8), reg_date, 4) LIKE " & strTheDate.

ps!.. (strTheDate is asp variable..)

I have debugged the strTheDate and i know it's the correct format : 24.12.03 ex.

ps!.. the field is a DateTime format, just to ensure that :)

Best reagards
Mirador|||Can;t say I think this is the best way of doing this, but I haven't had enough coffee to do a re-write (and blindman will undercut me anyway).

Try this (note the single quotes!):

SELECT bla1, bla2, bla3, bla4 FROM TABLE WHERE blabla = 1 and blabla = 0 and CONVERT(char(8), reg_date, 4) = CONVERT(char(8), CAST('" & strTheDate & "' AS DATETIME),4)

This will convert strTheDate to the same format.